5x^2+4y^2=1

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Solution for 5x^2+4y^2=1 equation: 


Simplifying
5x2 + 4y2 = 1

Solving
5x2 + 4y2 = 1

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4y2' to each side of the equation.
5x2 + 4y2 + -4y2 = 1 + -4y2

Combine like terms: 4y2 + -4y2 = 0
5x2 + 0 = 1 + -4y2
5x2 = 1 + -4y2

Divide each side by '5'.
x2 = 0.2 + -0.8y2

Simplifying
x2 = 0.2 + -0.8y2

Reorder the terms:
-0.2 + x2 + 0.8y2 = 0.2 + -0.8y2 + -0.2 + 0.8y2

Reorder the terms:
-0.2 + x2 + 0.8y2 = 0.2 + -0.2 + -0.8y2 + 0.8y2

Combine like terms: 0.2 + -0.2 = 0.0
-0.2 + x2 + 0.8y2 = 0.0 + -0.8y2 + 0.8y2
-0.2 + x2 + 0.8y2 = -0.8y2 + 0.8y2

Combine like terms: -0.8y2 + 0.8y2 = 0.0
-0.2 + x2 + 0.8y2 = 0.0

The solution to this equation could not be determined.

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